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99943321213 is a prime number
BaseRepresentation
bin101110100010100010…
…1100000111001111101
3100112222012222202120101
41131011011200321331
53114140442234323
6113525140121101
710135455133141
oct1350505407175
9315865882511
1099943321213
113942744352a
1217452996191
139569b563b8
144ba1709221
1528ee290dad
hex1745160e7d

99943321213 has 2 divisors, whose sum is σ = 99943321214. Its totient is φ = 99943321212.

The previous prime is 99943321211. The next prime is 99943321271. The reversal of 99943321213 is 31212334999.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78712791364 + 21230529849 = 280558^2 + 145707^2 .

It is a cyclic number.

It is not a de Polignac number, because 99943321213 - 21 = 99943321211 is a prime.

Together with 99943321211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99943321211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49971660606 + 49971660607.

It is an arithmetic number, because the mean of its divisors is an integer number (49971660607).

Almost surely, 299943321213 is an apocalyptic number.

It is an amenable number.

99943321213 is a deficient number, since it is larger than the sum of its proper divisors (1).

99943321213 is an equidigital number, since it uses as much as digits as its factorization.

99943321213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 314928, while the sum is 46.

The spelling of 99943321213 in words is "ninety-nine billion, nine hundred forty-three million, three hundred twenty-one thousand, two hundred thirteen".