999495000419 has 2 divisors, whose sum is σ = 999495000420. Its totient is φ = 999495000418.

The previous prime is 999495000407. The next prime is 999495000421. The reversal of 999495000419 is 914000594999.

999495000419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-999495000419 is a prime.

It is a super-2 number, since 2×999495000419² (a number of 25 digits) contains 22 as substring.

Together with 999495000421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (999495000499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499747500209 + 499747500210.

It is an arithmetic number, because the mean of its divisors is an integer number (499747500210).

Almost surely, 2^999495000419 is an apocalyptic number.

999495000419 is a deficient number, since it is larger than the sum of its proper divisors (1).

999495000419 is an equidigital number, since it uses as much as digits as its factorization.

999495000419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4723920, while the sum is 59.

The spelling of 999495000419 in words is "nine hundred ninety-nine billion, four hundred ninety-five million, four hundred nineteen", and thus it is an aban number.