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999495000421 is a prime number
BaseRepresentation
bin11101000101101101000…
…10110110000101100101
310112112212112011210021221
432202312202312011211
5112333431210003141
62043054530340341
7132132263220031
oct16426642660545
93475775153257
10999495000421
11355979964275
12141860a2a6b1
1373337782c18
143653934d1c1
151aeec261bd1
hexe8b68b6165

999495000421 has 2 divisors, whose sum is σ = 999495000422. Its totient is φ = 999495000420.

The previous prime is 999495000419. The next prime is 999495000443. The reversal of 999495000421 is 124000594999.

It is a happy number.

999495000421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 923547908196 + 75947092225 = 961014^2 + 275585^2 .

It is a cyclic number.

It is not a de Polignac number, because 999495000421 - 21 = 999495000419 is a prime.

Together with 999495000419, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999495040421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499747500210 + 499747500211.

It is an arithmetic number, because the mean of its divisors is an integer number (499747500211).

Almost surely, 2999495000421 is an apocalyptic number.

It is an amenable number.

999495000421 is a deficient number, since it is larger than the sum of its proper divisors (1).

999495000421 is an equidigital number, since it uses as much as digits as its factorization.

999495000421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1049760, while the sum is 52.

The spelling of 999495000421 in words is "nine hundred ninety-nine billion, four hundred ninety-five million, four hundred twenty-one", and thus it is an aban number.