9997000493 has 2 divisors, whose sum is σ = 9997000494. Its totient is φ = 9997000492.

The previous prime is 9997000463. The next prime is 9997000523. The reversal of 9997000493 is 3940007999.

9997000493 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (9997000463) and next prime (9997000523).

It can be written as a sum of positive squares in only one way, i.e., 9713482249 + 283518244 = 98557^2 + 16838^2 .

It is a cyclic number.

It is not a de Polignac number, because 9997000493 - 2¹⁰ = 9996999469 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9997000463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4998500246 + 4998500247.

It is an arithmetic number, because the mean of its divisors is an integer number (4998500247).

Almost surely, 2^9997000493 is an apocalyptic number.

It is an amenable number.

9997000493 is a deficient number, since it is larger than the sum of its proper divisors (1).

9997000493 is an equidigital number, since it uses as much as digits as its factorization.

9997000493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 551124, while the sum is 50.

The square root of 9997000493 is about 99985.0013402010. The cubic root of 9997000493 is about 2154.2192604266.

The spelling of 9997000493 in words is "nine billion, nine hundred ninety-seven million, four hundred ninety-three", and thus it is an aban number.