Base | Representation |
---|---|
bin | 10010100111110111… |
… | …11001000011010111 |
3 | 221210210021022202122 |
4 | 21103323321003113 |
5 | 130434011044303 |
6 | 4332034530155 |
7 | 502522551002 |
oct | 112373710327 |
9 | 27723238678 |
10 | 9998143703 |
11 | 4270767389 |
12 | 1b3043695b |
13 | c344ba582 |
14 | 6abbdc539 |
15 | 3d7b42e38 |
hex | 253ef90d7 |
9998143703 has 4 divisors (see below), whose sum is σ = 10053382248. Its totient is φ = 9942905160.
The previous prime is 9998143697. The next prime is 9998143709. The reversal of 9998143703 is 3073418999.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (9998143697) and next prime (9998143709).
It is a cyclic number.
It is not a de Polignac number, because 9998143703 - 212 = 9998139607 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (9998143709) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27619001 + ... + 27619362.
It is an arithmetic number, because the mean of its divisors is an integer number (2513345562).
Almost surely, 29998143703 is an apocalyptic number.
9998143703 is a deficient number, since it is larger than the sum of its proper divisors (55238545).
9998143703 is a wasteful number, since it uses less digits than its factorization.
9998143703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55238544.
The product of its (nonzero) digits is 1469664, while the sum is 53.
The square root of 9998143703 is about 99990.7180842302. The cubic root of 9998143703 is about 2154.3013727606.
The spelling of 9998143703 in words is "nine billion, nine hundred ninety-eight million, one hundred forty-three thousand, seven hundred three".
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