10000000993 has 2 divisors, whose sum is σ = 10000000994. Its totient is φ = 10000000992.

The previous prime is 10000000991. The next prime is 10000000999. The reversal of 10000000993 is 39900000001.

10000000993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9271378944 + 728622049 = 96288^2 + 26993^2 .

It is a cyclic number.

It is not a de Polignac number, because 10000000993 - 2¹ = 10000000991 is a prime.

Together with 10000000991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10000000991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000000496 + 5000000497.

It is an arithmetic number, because the mean of its divisors is an integer number (5000000497).

Almost surely, 2^10000000993 is an apocalyptic number.

It is an amenable number.

10000000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000000993 is an equidigital number, since it uses as much as digits as its factorization.

10000000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 10000000993 its reverse (39900000001), we get a palindrome (49900000994).

The spelling of 10000000993 in words is "ten billion, nine hundred ninety-three", and thus it is an aban number.