10000001000131 has 2 divisors, whose sum is σ = 10000001000132. Its totient is φ = 10000001000130.

The previous prime is 10000001000123. The next prime is 10000001000141. The reversal of 10000001000131 is 13100010000001.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10000001000131 - 2³ = 10000001000123 is a prime.

It is a super-2 number, since 2×10000001000131² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10000001000141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000000500065 + 5000000500066.

It is an arithmetic number, because the mean of its divisors is an integer number (5000000500066).

Almost surely, 2^{10000001000131} is an apocalyptic number.

10000001000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000001000131 is an equidigital number, since it uses as much as digits as its factorization.

10000001000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 7.

Adding to 10000001000131 its reverse (13100010000001), we get a palindrome (23100011000132).

The spelling of 10000001000131 in words is "ten trillion, one million, one hundred thirty-one", and thus it is an aban number.