100000011110113 has 2 divisors, whose sum is σ = 100000011110114. Its totient is φ = 100000011110112.

The previous prime is 100000011110081. The next prime is 100000011110117. The reversal of 100000011110113 is 311011110000001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96003802211409 + 3996208898704 = 9798153^2 + 1999052^2 .

It is an emirp because it is prime and its reverse (311011110000001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100000011110113 - 2⁵ = 100000011110081 is a prime.

It is a super-2 number, since 2×100000011110113² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100000011110113.

It is not a weakly prime, because it can be changed into another prime (100000011110117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000005555056 + 50000005555057.

It is an arithmetic number, because the mean of its divisors is an integer number (50000005555057).

Almost surely, 2^{100000011110113} is an apocalyptic number.

It is an amenable number.

100000011110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100000011110113 is an equidigital number, since it uses as much as digits as its factorization.

100000011110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 100000011110113 its reverse (311011110000001), we get a palindrome (411011121110114).

The spelling of 100000011110113 in words is "one hundred trillion, eleven million, one hundred ten thousand, one hundred thirteen".