Base | Representation |
---|---|
bin | 1001000110000100111100… |
… | …0110100111100101001111 |
3 | 1022101222202221221010012002 |
4 | 2101201033012213211033 |
5 | 2302320010304001033 |
6 | 33133535220502515 |
7 | 2051322411010553 |
oct | 221411706474517 |
9 | 38358687833162 |
10 | 10000011000143 |
11 | 3205a8756764a |
12 | 115609b54aa3b |
13 | 576cc650a398 |
14 | 268008793863 |
15 | 1251cadb73e8 |
hex | 9184f1a794f |
10000011000143 has 2 divisors, whose sum is σ = 10000011000144. Its totient is φ = 10000011000142.
The previous prime is 10000011000101. The next prime is 10000011000157. The reversal of 10000011000143 is 34100011000001.
10000011000143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10000011000143 - 210 = 10000010999119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10000011000193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000005500071 + 5000005500072.
It is an arithmetic number, because the mean of its divisors is an integer number (5000005500072).
Almost surely, 210000011000143 is an apocalyptic number.
10000011000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10000011000143 is an equidigital number, since it uses as much as digits as its factorization.
10000011000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 10000011000143 its reverse (34100011000001), we get a palindrome (44100022000144).
The spelling of 10000011000143 in words is "ten trillion, eleven million, one hundred forty-three", and thus it is an aban number.
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