Base | Representation |
---|---|
bin | 101110100100001111… |
… | …0111011000000000111 |
3 | 100120010012020021002022 |
4 | 1131020132323000013 |
5 | 3114300040011401 |
6 | 113534533433355 |
7 | 10140046432031 |
oct | 1351036730007 |
9 | 316105207068 |
10 | 100000313351 |
11 | 3945662a574 |
12 | 17469a9b85b |
13 | 95788bc263 |
14 | 4ba9102c51 |
15 | 290429c71b |
hex | 17487bb007 |
100000313351 has 2 divisors, whose sum is σ = 100000313352. Its totient is φ = 100000313350.
The previous prime is 100000313333. The next prime is 100000313359. The reversal of 100000313351 is 153313000001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100000313351 - 214 = 100000296967 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100000313359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000156675 + 50000156676.
It is an arithmetic number, because the mean of its divisors is an integer number (50000156676).
Almost surely, 2100000313351 is an apocalyptic number.
100000313351 is a deficient number, since it is larger than the sum of its proper divisors (1).
100000313351 is an equidigital number, since it uses as much as digits as its factorization.
100000313351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 17.
Adding to 100000313351 its reverse (153313000001), we get a palindrome (253313313352).
The spelling of 100000313351 in words is "one hundred billion, three hundred thirteen thousand, three hundred fifty-one".
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