100001000000119 has 2 divisors, whose sum is σ = 100001000000120. Its totient is φ = 100001000000118.

The previous prime is 100001000000071. The next prime is 100001000000191. The reversal of 100001000000119 is 911000000100001.

Together with next prime (100001000000191) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100001000000119 - 2¹⁷ = 100000999869047 is a prime.

It is a super-2 number, since 2×100001000000119² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100001000000099 and 100001000000108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100001000006119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000500000059 + 50000500000060.

It is an arithmetic number, because the mean of its divisors is an integer number (50000500000060).

Almost surely, 2^{100001000000119} is an apocalyptic number.

100001000000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

100001000000119 is an equidigital number, since it uses as much as digits as its factorization.

100001000000119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

The spelling of 100001000000119 in words is "one hundred trillion, one billion, one hundred nineteen", and thus it is an aban number.