Base | Representation |
---|---|
bin | 10110101111001101010011… |
… | …010011001110000011010111 |
3 | 111010002000101001212022100121 |
4 | 112233031103103032003113 |
5 | 101101404244000144431 |
6 | 552403514131452411 |
7 | 30030562001265316 |
oct | 2657152323160327 |
9 | 433060331768317 |
10 | 100001121099991 |
11 | 299552679231a1 |
12 | b270a79157107 |
13 | 43a50b04a3917 |
14 | 1a9a119a8427d |
15 | b863d2e22611 |
hex | 5af3534ce0d7 |
100001121099991 has 2 divisors, whose sum is σ = 100001121099992. Its totient is φ = 100001121099990.
The previous prime is 100001121099947. The next prime is 100001121100163. The reversal of 100001121099991 is 199990121100001.
It is a weak prime.
It is an emirp because it is prime and its reverse (199990121100001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100001121099991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100001121099931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000560549995 + 50000560549996.
It is an arithmetic number, because the mean of its divisors is an integer number (50000560549996).
Almost surely, 2100001121099991 is an apocalyptic number.
100001121099991 is a deficient number, since it is larger than the sum of its proper divisors (1).
100001121099991 is an equidigital number, since it uses as much as digits as its factorization.
100001121099991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 43.
Adding to 100001121099991 its reverse (199990121100001), we get a palindrome (299991242199992).
The spelling of 100001121099991 in words is "one hundred trillion, one billion, one hundred twenty-one million, ninety-nine thousand, nine hundred ninety-one".
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