Base | Representation |
---|---|
bin | 10110101111001101011110… |
… | …000011001000001110101001 |
3 | 111010002000211122012002021121 |
4 | 112233031132003020032221 |
5 | 101101410131131244314 |
6 | 552403544052535241 |
7 | 30030566321133313 |
oct | 2657153603101651 |
9 | 433060748162247 |
10 | 100001301431209 |
11 | 2995534a6a1762 |
12 | b270b09621521 |
13 | 43a510b962499 |
14 | 1a9a1359c67b3 |
15 | b863e3b93d24 |
hex | 5af35e0c83a9 |
100001301431209 has 2 divisors, whose sum is σ = 100001301431210. Its totient is φ = 100001301431208.
The previous prime is 100001301431191. The next prime is 100001301431233. The reversal of 100001301431209 is 902134103100001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 59778751915584 + 40222549515625 = 7731672^2 + 6342125^2 .
It is a cyclic number.
It is not a de Polignac number, because 100001301431209 - 217 = 100001301300137 is a prime.
It is a super-3 number, since 3×1000013014312093 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (100001301431279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50000650715604 + 50000650715605.
It is an arithmetic number, because the mean of its divisors is an integer number (50000650715605).
Almost surely, 2100001301431209 is an apocalyptic number.
It is an amenable number.
100001301431209 is a deficient number, since it is larger than the sum of its proper divisors (1).
100001301431209 is an equidigital number, since it uses as much as digits as its factorization.
100001301431209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 100001301431209 in words is "one hundred trillion, one billion, three hundred one million, four hundred thirty-one thousand, two hundred nine".
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