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1000013024347 is a prime number
BaseRepresentation
bin11101000110101010110…
…10111100110001011011
310112121012121221010112021
432203111122330301123
5112341011313234342
62043222153355311
7132151153312621
oct16432532746133
93477177833467
101000013024347
11356115311317
12141986408b37
13733baba8b5c
1436588077511
151b02c98a567
hexe8d56bcc5b

1000013024347 has 2 divisors, whose sum is σ = 1000013024348. Its totient is φ = 1000013024346.

The previous prime is 1000013024281. The next prime is 1000013024359. The reversal of 1000013024347 is 7434203100001.

It is a strong prime.

It is an emirp because it is prime and its reverse (7434203100001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000013024347 - 223 = 1000004635739 is a prime.

It is a super-2 number, since 2×10000130243472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1000013024047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500006512173 + 500006512174.

It is an arithmetic number, because the mean of its divisors is an integer number (500006512174).

Almost surely, 21000013024347 is an apocalyptic number.

1000013024347 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000013024347 is an equidigital number, since it uses as much as digits as its factorization.

1000013024347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 1000013024347 its reverse (7434203100001), we get a palindrome (8434216124348).

The spelling of 1000013024347 in words is "one trillion, thirteen million, twenty-four thousand, three hundred forty-seven".