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1000043321353 is a prime number
BaseRepresentation
bin11101000110101110011…
…10100001100000001001
310112121021201221101012121
432203113032201200021
5112341042042240403
62043225155011241
7132152001656236
oct16432716414011
93477251841177
101000043321353
1135613042496a
12141994599b21
13733c425608b
143658c0c278d
151b0304723bd
hexe8d73a1809

1000043321353 has 2 divisors, whose sum is σ = 1000043321354. Its totient is φ = 1000043321352.

The previous prime is 1000043321297. The next prime is 1000043321371. The reversal of 1000043321353 is 3531233400001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 964349532169 + 35693789184 = 982013^2 + 188928^2 .

It is an emirp because it is prime and its reverse (3531233400001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000043321353 - 29 = 1000043320841 is a prime.

It is not a weakly prime, because it can be changed into another prime (1000043361353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500021660676 + 500021660677.

It is an arithmetic number, because the mean of its divisors is an integer number (500021660677).

Almost surely, 21000043321353 is an apocalyptic number.

It is an amenable number.

1000043321353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000043321353 is an equidigital number, since it uses as much as digits as its factorization.

1000043321353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 1000043321353 its reverse (3531233400001), we get a palindrome (4531276721354).

The spelling of 1000043321353 in words is "one trillion, forty-three million, three hundred twenty-one thousand, three hundred fifty-three".