10000498117 has 2 divisors, whose sum is σ = 10000498118. Its totient is φ = 10000498116.

The previous prime is 10000498111. The next prime is 10000498129. The reversal of 10000498117 is 71189400001.

10000498117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10000200001 + 298116 = 100001^2 + 546^2 .

It is a cyclic number.

It is not a de Polignac number, because 10000498117 - 2²³ = 9992109509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10000498111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000249058 + 5000249059.

It is an arithmetic number, because the mean of its divisors is an integer number (5000249059).

Almost surely, 2^10000498117 is an apocalyptic number.

It is an amenable number.

10000498117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10000498117 is an equidigital number, since it uses as much as digits as its factorization.

10000498117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 31.

Adding to 10000498117 its reverse (71189400001), we get a palindrome (81189898118).

The spelling of 10000498117 in words is "ten billion, four hundred ninety-eight thousand, one hundred seventeen".