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100010000141 is a prime number
BaseRepresentation
bin101110100100100001…
…1110111111100001101
3100120010212110101212022
41131021003313330031
53114310030001031
6113535521215525
710140224655302
oct1351103677415
9316125411768
10100010000141
1139461046387
12174711915a5
13957a90139c
144baa5050a9
15290506297b
hex17490f7f0d

100010000141 has 2 divisors, whose sum is σ = 100010000142. Its totient is φ = 100010000140.

The previous prime is 100010000107. The next prime is 100010000183. The reversal of 100010000141 is 141000010001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99976116100 + 33884041 = 316190^2 + 5821^2 .

It is an emirp because it is prime and its reverse (141000010001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100010000141 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100010006141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005000070 + 50005000071.

It is an arithmetic number, because the mean of its divisors is an integer number (50005000071).

Almost surely, 2100010000141 is an apocalyptic number.

It is an amenable number.

100010000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

100010000141 is an equidigital number, since it uses as much as digits as its factorization.

100010000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 100010000141 its reverse (141000010001), we get a palindrome (241010010142).

The spelling of 100010000141 in words is "one hundred billion, ten million, one hundred forty-one", and thus it is an aban number.