Base | Representation |
---|---|
bin | 101110100100100010… |
… | …0010000010100001111 |
3 | 100120010212122110211011 |
4 | 1131021010100110033 |
5 | 3114310041144413 |
6 | 113535523310051 |
7 | 10140225552343 |
oct | 1351104202417 |
9 | 316125573734 |
10 | 100010099983 |
11 | 394611043a2 |
12 | 1747121b327 |
13 | 957a937971 |
14 | 4baa52d623 |
15 | 290508233d |
hex | 174911050f |
100010099983 has 2 divisors, whose sum is σ = 100010099984. Its totient is φ = 100010099982.
The previous prime is 100010099963. The next prime is 100010100011. The reversal of 100010099983 is 389990010001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100010099983 - 25 = 100010099951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100010099963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005049991 + 50005049992.
It is an arithmetic number, because the mean of its divisors is an integer number (50005049992).
Almost surely, 2100010099983 is an apocalyptic number.
100010099983 is a deficient number, since it is larger than the sum of its proper divisors (1).
100010099983 is an equidigital number, since it uses as much as digits as its factorization.
100010099983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 40.
It can be divided in two parts, 10001009998 and 3, that added together give a palindrome (10001010001).
The spelling of 100010099983 in words is "one hundred billion, ten million, ninety-nine thousand, nine hundred eighty-three".
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