Base | Representation |
---|---|
bin | 101110100100100010… |
… | …0101101101001011011 |
3 | 100120010212212120121210 |
4 | 1131021010231221123 |
5 | 3114310104020443 |
6 | 113535530034203 |
7 | 10140226562532 |
oct | 1351104555133 |
9 | 316125776553 |
10 | 100010220123 |
11 | 39461186690 |
12 | 17471278963 |
13 | 957a97a558 |
14 | 4baa561319 |
15 | 29050a7c33 |
hex | 174912da5b |
100010220123 has 32 divisors (see below), whose sum is σ = 150345695232. Its totient is φ = 58585255200.
The previous prime is 100010220083. The next prime is 100010220127. The reversal of 100010220123 is 321022010001.
It is not a de Polignac number, because 100010220123 - 217 = 100010089051 is a prime.
It is a super-5 number, since 5×1000102201235 (a number of 56 digits) contains 55555 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100010220099 and 100010220108.
It is not an unprimeable number, because it can be changed into a prime (100010220127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 782536 + ... + 901322.
It is an arithmetic number, because the mean of its divisors is an integer number (4698302976).
Almost surely, 2100010220123 is an apocalyptic number.
100010220123 is a deficient number, since it is larger than the sum of its proper divisors (50335475109).
100010220123 is a wasteful number, since it uses less digits than its factorization.
100010220123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119655.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 100010220123 its reverse (321022010001), we get a palindrome (421032230124).
The spelling of 100010220123 in words is "one hundred billion, ten million, two hundred twenty thousand, one hundred twenty-three".
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