1351104555133 has 2 divisors, whose sum is σ = 1351104555134. Its totient is φ = 1351104555132.

The previous prime is 1351104555113. The next prime is 1351104555139. The reversal of 1351104555133 is 3315554011531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 967630277124 + 383474278009 = 983682^2 + 619253^2 .

It is a cyclic number.

It is not a de Polignac number, because 1351104555133 - 2³⁷ = 1213665601661 is a prime.

It is a super-2 number, since 2×1351104555133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1351104555092 and 1351104555101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1351104555139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675552277566 + 675552277567.

It is an arithmetic number, because the mean of its divisors is an integer number (675552277567).

Almost surely, 2^{1351104555133} is an apocalyptic number.

It is an amenable number.

1351104555133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1351104555133 is an equidigital number, since it uses as much as digits as its factorization.

1351104555133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67500, while the sum is 37.

Adding to 1351104555133 its reverse (3315554011531), we get a palindrome (4666658566664).

The spelling of 1351104555133 in words is "one trillion, three hundred fifty-one billion, one hundred four million, five hundred fifty-five thousand, one hundred thirty-three".