100011011000113 has 2 divisors, whose sum is σ = 100011011000114. Its totient is φ = 100011011000112.

The previous prime is 100011011000101. The next prime is 100011011000129. The reversal of 100011011000113 is 311000110110001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58223797724304 + 41787213275809 = 7630452^2 + 6464303^2 .

It is a cyclic number.

It is not a de Polignac number, because 100011011000113 - 2⁴¹ = 97811987744561 is a prime.

It is a super-4 number, since 4×100011011000113⁴ (a number of 57 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100011011000113.

It is not a weakly prime, because it can be changed into another prime (100011011009113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005505500056 + 50005505500057.

It is an arithmetic number, because the mean of its divisors is an integer number (50005505500057).

Almost surely, 2^{100011011000113} is an apocalyptic number.

It is an amenable number.

100011011000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011011000113 is an equidigital number, since it uses as much as digits as its factorization.

100011011000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 100011011000113 its reverse (311000110110001), we get a palindrome (411011121110114).

The spelling of 100011011000113 in words is "one hundred trillion, eleven billion, eleven million, one hundred thirteen", and thus it is an aban number.