Base | Representation |
---|---|
bin | 10110101111010110100000… |
… | …110010001100101001110011 |
3 | 111010002221220022110022222121 |
4 | 112233112200302030221303 |
5 | 101102040022304012242 |
6 | 552412231342415111 |
7 | 30031362041123644 |
oct | 2657264062145163 |
9 | 433087808408877 |
10 | 100011011000947 |
11 | 29959482479162 |
12 | b272979291497 |
13 | 43a5cc8422917 |
14 | 1a9a7b73476cb |
15 | b867b12d3667 |
hex | 5af5a0c8ca73 |
100011011000947 has 2 divisors, whose sum is σ = 100011011000948. Its totient is φ = 100011011000946.
The previous prime is 100011011000941. The next prime is 100011011000969. The reversal of 100011011000947 is 749000110110001.
It is a weak prime.
It is an emirp because it is prime and its reverse (749000110110001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100011011000947 is a prime.
It is not a weakly prime, because it can be changed into another prime (100011011000941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005505500473 + 50005505500474.
It is an arithmetic number, because the mean of its divisors is an integer number (50005505500474).
Almost surely, 2100011011000947 is an apocalyptic number.
100011011000947 is a deficient number, since it is larger than the sum of its proper divisors (1).
100011011000947 is an equidigital number, since it uses as much as digits as its factorization.
100011011000947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 100011011000947 its reverse (749000110110001), we get a palindrome (849011121110948).
The spelling of 100011011000947 in words is "one hundred trillion, eleven billion, eleven million, nine hundred forty-seven", and thus it is an aban number.
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