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1000111023113 is a prime number
BaseRepresentation
bin11101000110110110100…
…00110010010000001001
310112121110110022222120012
432203123100302100021
5112341211410214423
62043240014041305
7132153453301406
oct16433320622011
93477413288505
101000111023113
11356165666234
121419b31a9235
137340529b7a7
14365970a72ad
151b036397078
hexe8db432409

1000111023113 has 2 divisors, whose sum is σ = 1000111023114. Its totient is φ = 1000111023112.

The previous prime is 1000111023101. The next prime is 1000111023167. The reversal of 1000111023113 is 3113201110001.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975488078224 + 24622944889 = 987668^2 + 156917^2 .

It is an emirp because it is prime and its reverse (3113201110001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000111023113 - 220 = 1000109974537 is a prime.

It is not a weakly prime, because it can be changed into another prime (1000111023173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055511556 + 500055511557.

It is an arithmetic number, because the mean of its divisors is an integer number (500055511557).

Almost surely, 21000111023113 is an apocalyptic number.

It is an amenable number.

1000111023113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000111023113 is an equidigital number, since it uses as much as digits as its factorization.

1000111023113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1000111023113 its reverse (3113201110001), we get a palindrome (4113312133114).

The spelling of 1000111023113 in words is "one trillion, one hundred eleven million, twenty-three thousand, one hundred thirteen".