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100011110109983 is a prime number
BaseRepresentation
bin10110101111010110100110…
…101100010001001100011111
3111010002222011012221121000122
4112233112212230101030133
5101102040223142004413
6552412245242545155
730031364353415402
oct2657264654211437
9433088135847018
10100011110109983
1129959523411256
12b2729a65081bb
1343a6012b13a17
141a9a7c6585d39
15b867b9d5e108
hex5af5a6b1131f

100011110109983 has 2 divisors, whose sum is σ = 100011110109984. Its totient is φ = 100011110109982.

The previous prime is 100011110109971. The next prime is 100011110110001. The reversal of 100011110109983 is 389901011110001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100011110109983 - 212 = 100011110105887 is a prime.

It is a super-2 number, since 2×1000111101099832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100011110109913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50005555054991 + 50005555054992.

It is an arithmetic number, because the mean of its divisors is an integer number (50005555054992).

Almost surely, 2100011110109983 is an apocalyptic number.

100011110109983 is a deficient number, since it is larger than the sum of its proper divisors (1).

100011110109983 is an equidigital number, since it uses as much as digits as its factorization.

100011110109983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 35.

Adding to 100011110109983 its reverse (389901011110001), we get a palindrome (489912121219984).

The spelling of 100011110109983 in words is "one hundred trillion, eleven billion, one hundred ten million, one hundred nine thousand, nine hundred eighty-three".