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1000111997 is a prime number
BaseRepresentation
bin111011100111000…
…111111101111101
32120200212221202002
4323213013331331
54022012040442
6243123512045
733532545263
oct7347077575
92520787662
101000111997
1147359aa45
1223ab28625
1312c279161
1496b7a433
155cc04732
hex3b9c7f7d

1000111997 has 2 divisors, whose sum is σ = 1000111998. Its totient is φ = 1000111996.

The previous prime is 1000111979. The next prime is 1000112011. The reversal of 1000111997 is 7991110001.

Together with previous prime (1000111979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 683770201 + 316341796 = 26149^2 + 17786^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000111997 - 28 = 1000111741 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000111597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500055998 + 500055999.

It is an arithmetic number, because the mean of its divisors is an integer number (500055999).

Almost surely, 21000111997 is an apocalyptic number.

It is an amenable number.

1000111997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000111997 is an equidigital number, since it uses as much as digits as its factorization.

1000111997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567, while the sum is 29.

The square root of 1000111997 is about 31624.5473801602. The cubic root of 1000111997 is about 1000.0373309397.

Adding to 1000111997 its reverse (7991110001), we get a palindrome (8991221998).

The spelling of 1000111997 in words is "one billion, one hundred eleven thousand, nine hundred ninety-seven".