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1000113123253 is a prime number
BaseRepresentation
bin11101000110110110110…
…00110010111110110101
310112121110121021200102011
432203123120302332311
5112341212424421003
62043240131044221
7132153510166306
oct16433330627665
93477417250364
101000113123253
11356166870092
121419b3a40671
137340585568a
14365974927ad
151b03665e46d
hexe8db632fb5

1000113123253 has 2 divisors, whose sum is σ = 1000113123254. Its totient is φ = 1000113123252.

The previous prime is 1000113123239. The next prime is 1000113123319. The reversal of 1000113123253 is 3523213110001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 876361844164 + 123751279089 = 936142^2 + 351783^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000113123253 - 217 = 1000112992181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000113123203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500056561626 + 500056561627.

It is an arithmetic number, because the mean of its divisors is an integer number (500056561627).

Almost surely, 21000113123253 is an apocalyptic number.

It is an amenable number.

1000113123253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000113123253 is an equidigital number, since it uses as much as digits as its factorization.

1000113123253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 1000113123253 its reverse (3523213110001), we get a palindrome (4523326233254).

The spelling of 1000113123253 in words is "one trillion, one hundred thirteen million, one hundred twenty-three thousand, two hundred fifty-three".