10001131511321 has 2 divisors, whose sum is σ = 10001131511322. Its totient is φ = 10001131511320.

The previous prime is 10001131511201. The next prime is 10001131511323. The reversal of 10001131511321 is 12311513110001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9843347782921 + 157783728400 = 3137411^2 + 397220^2 .

It is a cyclic number.

It is not a de Polignac number, because 10001131511321 - 2³⁰ = 10000057769497 is a prime.

Together with 10001131511323, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10001131511293 and 10001131511302.

It is not a weakly prime, because it can be changed into another prime (10001131511323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000565755660 + 5000565755661.

It is an arithmetic number, because the mean of its divisors is an integer number (5000565755661).

Almost surely, 2^{10001131511321} is an apocalyptic number.

It is an amenable number.

10001131511321 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001131511321 is an equidigital number, since it uses as much as digits as its factorization.

10001131511321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 20.

Adding to 10001131511321 its reverse (12311513110001), we get a palindrome (22312644621322).

The spelling of 10001131511321 in words is "ten trillion, one billion, one hundred thirty-one million, five hundred eleven thousand, three hundred twenty-one".