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100012012020110 = 2510001201202011
BaseRepresentation
bin10110101111010111011100…
…011100110010000110001110
3111010010001111002001101010102
4112233113130130302012032
5101102044100034120420
6552412514542011102
730031425614501111
oct2657273434620616
9433101432041112
10100012012020110
1129959946528723
12b272bb8576a92
1343a6127928958
141a9a87027c578
15b8681e116a75
hex5af5dc73218e

100012012020110 has 8 divisors (see below), whose sum is σ = 180021621636216. Its totient is φ = 40004804808040.

The previous prime is 100012012020101. The next prime is 100012012020127. The reversal of 100012012020110 is 11020210210001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 100012012020091 and 100012012020100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000600600996 + ... + 5000600601015.

It is an arithmetic number, because the mean of its divisors is an integer number (22502702704527).

Almost surely, 2100012012020110 is an apocalyptic number.

100012012020110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

100012012020110 is a deficient number, since it is larger than the sum of its proper divisors (80009609616106).

100012012020110 is a wasteful number, since it uses less digits than its factorization.

100012012020110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10001201202018.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 100012012020110 its reverse (11020210210001), we get a palindrome (111032222230111).

The spelling of 100012012020110 in words is "one hundred trillion, twelve billion, twelve million, twenty thousand, one hundred ten".

Divisors: 1 2 5 10 10001201202011 20002402404022 50006006010055 100012012020110