1000120443401 has 2 divisors, whose sum is σ = 1000120443402. Its totient is φ = 1000120443400.

The previous prime is 1000120443391. The next prime is 1000120443403. The reversal of 1000120443401 is 1043440210001.

1000120443401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 678812857801 + 321307585600 = 823901^2 + 566840^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000120443401 - 2¹⁸ = 1000120181257 is a prime.

It is a super-2 number, since 2×1000120443401² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1000120443403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1000120443403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500060221700 + 500060221701.

It is an arithmetic number, because the mean of its divisors is an integer number (500060221701).

Almost surely, 2^{1000120443401} is an apocalyptic number.

It is an amenable number.

1000120443401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000120443401 is an equidigital number, since it uses as much as digits as its factorization.

1000120443401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1000120443401 its reverse (1043440210001), we get a palindrome (2043560653402).

The spelling of 1000120443401 in words is "one trillion, one hundred twenty million, four hundred forty-three thousand, four hundred one".