Base | Representation |
---|---|
bin | 11101000110110111101… |
… | …10111011011000000001 |
3 | 10112121111011010222101121 |
4 | 32203123312323120001 |
5 | 112341221440200303 |
6 | 2043241012232241 |
7 | 132153634264504 |
oct | 16433366733001 |
9 | 3477434128347 |
10 | 1000121021953 |
11 | 356170275539 |
12 | 1419b660b681 |
13 | 7340738c971 |
14 | 3659854b13b |
15 | 1b0371be9bd |
hex | e8dbdbb601 |
1000121021953 has 2 divisors, whose sum is σ = 1000121021954. Its totient is φ = 1000121021952.
The previous prime is 1000121021873. The next prime is 1000121021957. The reversal of 1000121021953 is 3591201210001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 991203430464 + 8917591489 = 995592^2 + 94433^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000121021953 - 233 = 991531087361 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000121021957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500060510976 + 500060510977.
It is an arithmetic number, because the mean of its divisors is an integer number (500060510977).
Almost surely, 21000121021953 is an apocalyptic number.
It is an amenable number.
1000121021953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000121021953 is an equidigital number, since it uses as much as digits as its factorization.
1000121021953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 1000121021953 its reverse (3591201210001), we get a palindrome (4591322231954).
The spelling of 1000121021953 in words is "one trillion, one hundred twenty-one million, twenty-one thousand, nine hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •