Base | Representation |
---|---|
bin | 11101000110110111110… |
… | …11000111011110110001 |
3 | 10112121111020012202210012 |
4 | 32203123323013132301 |
5 | 112341222230320423 |
6 | 2043241051544305 |
7 | 132153646520234 |
oct | 16433373073661 |
9 | 3477436182705 |
10 | 1000122120113 |
11 | 356170955606 |
12 | 1419b6a5b095 |
13 | 7340768576c |
14 | 3659875541b |
15 | 1b03733a078 |
hex | e8dbec77b1 |
1000122120113 has 2 divisors, whose sum is σ = 1000122120114. Its totient is φ = 1000122120112.
The previous prime is 1000122120091. The next prime is 1000122120181. The reversal of 1000122120113 is 3110212210001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 619671244864 + 380450875249 = 787192^2 + 616807^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000122120113 - 210 = 1000122119089 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1000122120713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500061060056 + 500061060057.
It is an arithmetic number, because the mean of its divisors is an integer number (500061060057).
Almost surely, 21000122120113 is an apocalyptic number.
It is an amenable number.
1000122120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000122120113 is an equidigital number, since it uses as much as digits as its factorization.
1000122120113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1000122120113 its reverse (3110212210001), we get a palindrome (4110334330114).
The spelling of 1000122120113 in words is "one trillion, one hundred twenty-two million, one hundred twenty thousand, one hundred thirteen".
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