Base | Representation |
---|---|
bin | 10010101000001111… |
… | …01001011011111111 |
3 | 221211000001220011012 |
4 | 21110013221123333 |
5 | 130440303203341 |
6 | 4332224545435 |
7 | 502561004516 |
oct | 112407513377 |
9 | 27730056135 |
10 | 10001225471 |
11 | 42724817a6 |
12 | 1b3148227b |
13 | c350291c3 |
14 | 6ac3a167d |
15 | 3d80510eb |
hex | 2541e96ff |
10001225471 has 2 divisors, whose sum is σ = 10001225472. Its totient is φ = 10001225470.
The previous prime is 10001225441. The next prime is 10001225483. The reversal of 10001225471 is 17452210001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10001225471 - 210 = 10001224447 is a prime.
It is a super-3 number, since 3×100012254713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10001225411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000612735 + 5000612736.
It is an arithmetic number, because the mean of its divisors is an integer number (5000612736).
Almost surely, 210001225471 is an apocalyptic number.
10001225471 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001225471 is an equidigital number, since it uses as much as digits as its factorization.
10001225471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 10001225471 its reverse (17452210001), we get a palindrome (27453435472).
The spelling of 10001225471 in words is "ten billion, one million, two hundred twenty-five thousand, four hundred seventy-one".
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