Base | Representation |
---|---|
bin | 1001000110001001011111… |
… | …1100100111000000011111 |
3 | 1022102002221010112220000122 |
4 | 2101202113330213000133 |
5 | 2302330011134104434 |
6 | 33134300354545155 |
7 | 2051364610545263 |
oct | 221422774470037 |
9 | 38362833486018 |
10 | 10001233113119 |
11 | 32065543a7176 |
12 | 11563808981bb |
13 | 57715c774961 |
14 | 2680c2bdc0a3 |
15 | 12524d31ec2e |
hex | 91897f2701f |
10001233113119 has 2 divisors, whose sum is σ = 10001233113120. Its totient is φ = 10001233113118.
The previous prime is 10001233113103. The next prime is 10001233113239. The reversal of 10001233113119 is 91131133210001.
10001233113119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (91131133210001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10001233113119 - 24 = 10001233113103 is a prime.
It is a super-2 number, since 2×100012331131192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10001233103119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000616556559 + 5000616556560.
It is an arithmetic number, because the mean of its divisors is an integer number (5000616556560).
Almost surely, 210001233113119 is an apocalyptic number.
10001233113119 is a deficient number, since it is larger than the sum of its proper divisors (1).
10001233113119 is an equidigital number, since it uses as much as digits as its factorization.
10001233113119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 26.
The spelling of 10001233113119 in words is "ten trillion, one billion, two hundred thirty-three million, one hundred thirteen thousand, one hundred nineteen".
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