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100013120000 = 2954535897
BaseRepresentation
bin101110100100100111…
…1110001101000000000
3100120011002022220111122
41131021033301220000
53114311324320000
6113540112131412
710140263331143
oct1351117615000
9316132286448
10100013120000
1139462887382
1217472236b68
13957b454461
144baaab805a
15290547c085
hex17493f1a00

100013120000 has 200 divisors, whose sum is σ = 254463323796. Its totient is φ = 39243776000.

The previous prime is 100013119963. The next prime is 100013120017. The reversal of 100013120000 is 21310001.

100013120000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 10 ways, for example, as 631818496 + 99381301504 = 25136^2 + 315248^2 .

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a self number, because there is not a number n which added to its sum of digits gives 100013120000.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 16957052 + ... + 16962948.

Almost surely, 2100013120000 is an apocalyptic number.

100013120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100013120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (127231661898).

100013120000 is an abundant number, since it is smaller than the sum of its proper divisors (154450203796).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100013120000 is an frugal number, since it uses more digits than its factorization.

100013120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5988 (or 5957 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 100013120000 its reverse (21310001), we get a palindrome (100034430001).

The spelling of 100013120000 in words is "one hundred billion, thirteen million, one hundred twenty thousand".