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10001315079419 is a prime number
BaseRepresentation
bin1001000110001001110011…
…0101010010010011111011
31022102010010211210012122112
42101202130311102103323
52302330143130020134
633134312443442535
72051366624341136
oct221423465222373
938363124705575
1010001315079419
1132065966a0714
1211563a422644b
13577173743021
142680cda5721d
151252556111ce
hex9189cd524fb

10001315079419 has 2 divisors, whose sum is σ = 10001315079420. Its totient is φ = 10001315079418.

The previous prime is 10001315079383. The next prime is 10001315079421. The reversal of 10001315079419 is 91497051310001.

10001315079419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (91497051310001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10001315079419 is a prime.

It is a super-2 number, since 2×100013150794192 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10001315079421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10001315079319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5000657539709 + 5000657539710.

It is an arithmetic number, because the mean of its divisors is an integer number (5000657539710).

Almost surely, 210001315079419 is an apocalyptic number.

10001315079419 is a deficient number, since it is larger than the sum of its proper divisors (1).

10001315079419 is an equidigital number, since it uses as much as digits as its factorization.

10001315079419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34020, while the sum is 41.

The spelling of 10001315079419 in words is "ten trillion, one billion, three hundred fifteen million, seventy-nine thousand, four hundred nineteen".