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10002111220183 is a prime number
BaseRepresentation
bin1001000110001100110001…
…0010010100100111010111
31022102012012022212100110111
42101203030102110213113
52302333310433021213
633134523443503451
72051425432412215
oct221431422244727
938365168770414
1010002111220183
113206965035a95
121156586987b87
1357726c674434
14268167699cb5
151252a0474a3d
hex918cc4949d7

10002111220183 has 2 divisors, whose sum is σ = 10002111220184. Its totient is φ = 10002111220182.

The previous prime is 10002111220169. The next prime is 10002111220237. The reversal of 10002111220183 is 38102211120001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10002111220183 - 25 = 10002111220151 is a prime.

It is a super-2 number, since 2×100021112201832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10002111220133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001055610091 + 5001055610092.

It is an arithmetic number, because the mean of its divisors is an integer number (5001055610092).

Almost surely, 210002111220183 is an apocalyptic number.

10002111220183 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002111220183 is an equidigital number, since it uses as much as digits as its factorization.

10002111220183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 10002111220183 its reverse (38102211120001), we get a palindrome (48104322340184).

The spelling of 10002111220183 in words is "ten trillion, two billion, one hundred eleven million, two hundred twenty thousand, one hundred eighty-three".