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10002120000 = 26354174903
BaseRepresentation
bin10010101000010110…
…00011110101000000
3221211001202100012220
421110023003311000
5130441020320000
64332300051040
7502601421465
oct112413036500
927731670186
1010002120000
114272a32884
121b31833a80
13c35280402
146ac55566c
153d817b1a0
hex2542c3d40

10002120000 has 280 divisors, whose sum is σ = 35021739456. Its totient is φ = 2509824000.

The previous prime is 10002119947. The next prime is 10002120031. The reversal of 10002120000 is 2120001.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2037549 + ... + 2042451.

Almost surely, 210002120000 is an apocalyptic number.

10002120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10002120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17510869728).

10002120000 is an abundant number, since it is smaller than the sum of its proper divisors (25019619456).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10002120000 is an equidigital number, since it uses as much as digits as its factorization.

10002120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4955 (or 4930 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 6.

Adding to 10002120000 its reverse (2120001), we get a palindrome (10004240001).

Subtracting from 10002120000 its reverse (2120001), we obtain a palindrome (9999999999).

It can be divided in two parts, 100021 and 20000, that added together give a palindrome (120021).

The spelling of 10002120000 in words is "ten billion, two million, one hundred twenty thousand".