Base | Representation |
---|---|
bin | 1001000110001101000110… |
… | …1110010011111000110001 |
3 | 1022102012102200111222001221 |
4 | 2101203101232103320301 |
5 | 2302334002311141223 |
6 | 33134540503025041 |
7 | 2051430620660653 |
oct | 221432156237061 |
9 | 38365380458057 |
10 | 10002202443313 |
11 | 3206a01582303 |
12 | 11565b143b181 |
13 | 577285534012 |
14 | 2681758446d3 |
15 | 1252a8493b5d |
hex | 918d1b93e31 |
10002202443313 has 2 divisors, whose sum is σ = 10002202443314. Its totient is φ = 10002202443312.
The previous prime is 10002202443287. The next prime is 10002202443329. The reversal of 10002202443313 is 31334420220001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5807439678769 + 4194762764544 = 2409863^2 + 2048112^2 .
It is a cyclic number.
It is not a de Polignac number, because 10002202443313 - 29 = 10002202442801 is a prime.
It is not a weakly prime, because it can be changed into another prime (10002202443613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001101221656 + 5001101221657.
It is an arithmetic number, because the mean of its divisors is an integer number (5001101221657).
Almost surely, 210002202443313 is an apocalyptic number.
It is an amenable number.
10002202443313 is a deficient number, since it is larger than the sum of its proper divisors (1).
10002202443313 is an equidigital number, since it uses as much as digits as its factorization.
10002202443313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 10002202443313 its reverse (31334420220001), we get a palindrome (41336622663314).
The spelling of 10002202443313 in words is "ten trillion, two billion, two hundred two million, four hundred forty-three thousand, three hundred thirteen".
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