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10002212111 is a prime number
BaseRepresentation
bin10010101000010110…
…11010010100001111
3221211001221000120102
421110023122110033
5130441031241421
64332302041315
7502602254153
oct112413322417
927731830512
1010002212111
114272a96001
121b3187923b
13c352b3308
146ac57b063
153d819860b
hex2542da50f

10002212111 has 2 divisors, whose sum is σ = 10002212112. Its totient is φ = 10002212110.

The previous prime is 10002212083. The next prime is 10002212131. The reversal of 10002212111 is 11121220001.

10002212111 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11121220001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10002212111 - 222 = 9998017807 is a prime.

It is a super-3 number, since 3×100022121113 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10002212092 and 10002212101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10002212131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001106055 + 5001106056.

It is an arithmetic number, because the mean of its divisors is an integer number (5001106056).

Almost surely, 210002212111 is an apocalyptic number.

10002212111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002212111 is an equidigital number, since it uses as much as digits as its factorization.

10002212111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10002212111 its reverse (11121220001), we get a palindrome (21123432112).

The spelling of 10002212111 in words is "ten billion, two million, two hundred twelve thousand, one hundred eleven".