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1000234143011 is a prime number
BaseRepresentation
bin11101000111000101001…
…10011100110100100011
310112121210001000010022102
432203202212130310203
5112341434420034021
62043300133001015
7132156506635505
oct16434246346443
93477701003272
101000234143011
11356219109014
12141a2848316b
13734249487bc
14365a9595d75
151b0420b700b
hexe8e299cd23

1000234143011 has 2 divisors, whose sum is σ = 1000234143012. Its totient is φ = 1000234143010.

The previous prime is 1000234142951. The next prime is 1000234143031. The reversal of 1000234143011 is 1103414320001.

1000234143011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (1000234143031) can be obtained adding 1000234143011 to its sum of digits (20).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1000234143011 is a prime.

It is a super-2 number, since 2×10002341430112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1000234143031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500117071505 + 500117071506.

It is an arithmetic number, because the mean of its divisors is an integer number (500117071506).

Almost surely, 21000234143011 is an apocalyptic number.

1000234143011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000234143011 is an equidigital number, since it uses as much as digits as its factorization.

1000234143011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1000234143011 its reverse (1103414320001), we get a palindrome (2103648463012).

The spelling of 1000234143011 in words is "one trillion, two hundred thirty-four million, one hundred forty-three thousand, eleven".