Base | Representation |
---|---|
bin | 11101000111000101001… |
… | …11100011001100001001 |
3 | 10112121210001112202200121 |
4 | 32203202213203030021 |
5 | 112341440003244431 |
6 | 2043300143103241 |
7 | 132156512246023 |
oct | 16434247431411 |
9 | 3477701482617 |
10 | 1000234431241 |
11 | 356219295621 |
12 | 141a285a1b21 |
13 | 73424a19a56 |
14 | 365a962d013 |
15 | 1b042122611 |
hex | e8e29e3309 |
1000234431241 has 2 divisors, whose sum is σ = 1000234431242. Its totient is φ = 1000234431240.
The previous prime is 1000234431191. The next prime is 1000234431257. The reversal of 1000234431241 is 1421344320001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 595520890000 + 404713541241 = 771700^2 + 636171^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000234431241 - 223 = 1000226042633 is a prime.
It is not a weakly prime, because it can be changed into another prime (1000234431281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500117215620 + 500117215621.
It is an arithmetic number, because the mean of its divisors is an integer number (500117215621).
Almost surely, 21000234431241 is an apocalyptic number.
It is an amenable number.
1000234431241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000234431241 is an equidigital number, since it uses as much as digits as its factorization.
1000234431241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1000234431241 its reverse (1421344320001), we get a palindrome (2421578751242).
The spelling of 1000234431241 in words is "one trillion, two hundred thirty-four million, four hundred thirty-one thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •