100031142121 has 2 divisors, whose sum is σ = 100031142122. Its totient is φ = 100031142120.

The previous prime is 100031142019. The next prime is 100031142137. The reversal of 100031142121 is 121241130001.

It is an a-pointer prime, because the next prime (100031142137) can be obtained adding 100031142121 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81416632896 + 18614509225 = 285336^2 + 136435^2 .

It is a cyclic number.

It is not a de Polignac number, because 100031142121 - 2¹¹ = 100031140073 is a prime.

It is a super-4 number, since 4×100031142121⁴ (a number of 45 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100031142095 and 100031142104.

It is not a weakly prime, because it can be changed into another prime (100031142191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50015571060 + 50015571061.

It is an arithmetic number, because the mean of its divisors is an integer number (50015571061).

Almost surely, 2^100031142121 is an apocalyptic number.

It is an amenable number.

100031142121 is a deficient number, since it is larger than the sum of its proper divisors (1).

100031142121 is an equidigital number, since it uses as much as digits as its factorization.

100031142121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 100031142121 its reverse (121241130001), we get a palindrome (221272272122).

The spelling of 100031142121 in words is "one hundred billion, thirty-one million, one hundred forty-two thousand, one hundred twenty-one".