| Base | Representation |
|---|---|
| bin | 10010101000011101… |
| … | …11010101001111000 |
| 3 | 221211010122201001100 |
| 4 | 21110032322221320 |
| 5 | 130441300143000 |
| 6 | 4332333451400 |
| 7 | 502613132142 |
| oct | 112416725170 |
| 9 | 27733581040 |
| 10 | 10003131000 |
| 11 | 4273563415 |
| 12 | 1b32040b60 |
| 13 | c35545635 |
| 14 | 6ac739c92 |
| 15 | 3d82caa00 |
| hex | 2543baa78 |
10003131000 has 192 divisors, whose sum is σ = 33876198720. Its totient is φ = 2662329600.
The previous prime is 10003130989. The next prime is 10003131029. The reversal of 10003131000 is 13130001.
10003131000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×100031310002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7676349 + ... + 7677651.
It is an arithmetic number, because the mean of its divisors is an integer number (176438535).
Almost surely, 210003131000 is an apocalyptic number.
10003131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10003131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16938099360).
10003131000 is an abundant number, since it is smaller than the sum of its proper divisors (23873067720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10003131000 is a wasteful number, since it uses less digits than its factorization.
10003131000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2183 (or 2166 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 9.
Adding to 10003131000 its reverse (13130001), we get a palindrome (10016261001).
Subtracting from 10003131000 its reverse (13130001), we obtain a palindrome (9990000999).
The spelling of 10003131000 in words is "ten billion, three million, one hundred thirty-one thousand".
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