Base | Representation |
---|---|
bin | 10010101000011111… |
… | …00110101011010000 |
3 | 221211010222212101120 |
4 | 21110033212223100 |
5 | 130441321430222 |
6 | 4332341402240 |
7 | 502614512631 |
oct | 112417465320 |
9 | 27733885346 |
10 | 10003311312 |
11 | 4273676935 |
12 | 1b32109380 |
13 | c355a9727 |
14 | 6ac785888 |
15 | 3d831415c |
hex | 2543e6ad0 |
10003311312 has 40 divisors (see below), whose sum is σ = 25897759104. Its totient is φ = 3327227904.
The previous prime is 10003311299. The next prime is 10003311341. The reversal of 10003311312 is 21311330001.
It is a super-2 number, since 2×100033113122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10003311291 and 10003311300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 202833 + ... + 247280.
Almost surely, 210003311312 is an apocalyptic number.
10003311312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
10003311312 is an abundant number, since it is smaller than the sum of its proper divisors (15894447792).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10003311312 is a wasteful number, since it uses less digits than its factorization.
10003311312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 450587 (or 450581 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10003311312 its reverse (21311330001), we get a palindrome (31314641313).
The spelling of 10003311312 in words is "ten billion, three million, three hundred eleven thousand, three hundred twelve".
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