Base | Representation |
---|---|
bin | 1001000110010001001111… |
… | …0100101110101011000011 |
3 | 1022102022021222020221001002 |
4 | 2101210103310232223003 |
5 | 2302343240211002042 |
6 | 33135242520202215 |
7 | 2051500245101261 |
oct | 221442364565303 |
9 | 38368258227032 |
10 | 10003311422147 |
11 | 320742056a53a |
12 | 115686090936b |
13 | 577401209804 |
14 | 26823cc3d431 |
15 | 125320a00132 |
hex | 91913d2eac3 |
10003311422147 has 2 divisors, whose sum is σ = 10003311422148. Its totient is φ = 10003311422146.
The previous prime is 10003311422063. The next prime is 10003311422149. The reversal of 10003311422147 is 74122411330001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10003311422147 - 28 = 10003311421891 is a prime.
Together with 10003311422149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10003311422149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001655711073 + 5001655711074.
It is an arithmetic number, because the mean of its divisors is an integer number (5001655711074).
Almost surely, 210003311422147 is an apocalyptic number.
10003311422147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10003311422147 is an equidigital number, since it uses as much as digits as its factorization.
10003311422147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 10003311422147 its reverse (74122411330001), we get a palindrome (84125722752148).
The spelling of 10003311422147 in words is "ten trillion, three billion, three hundred eleven million, four hundred twenty-two thousand, one hundred forty-seven".
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