Base | Representation |
---|---|
bin | 101110100101001110… |
… | …0110011010111001001 |
3 | 100120012111022202222221 |
4 | 1131022130303113021 |
5 | 3114332011442301 |
6 | 113542113014041 |
7 | 10140630060424 |
oct | 1351234632711 |
9 | 316174282887 |
10 | 100033312201 |
11 | 39473219049 |
12 | 17478b54321 |
13 | 95826a41c4 |
14 | 4bad6529bb |
15 | 2907119da1 |
hex | 174a7335c9 |
100033312201 has 2 divisors, whose sum is σ = 100033312202. Its totient is φ = 100033312200.
The previous prime is 100033312199. The next prime is 100033312213. The reversal of 100033312201 is 102213330001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99257132601 + 776179600 = 315051^2 + 27860^2 .
It is a cyclic number.
It is not a de Polignac number, because 100033312201 - 21 = 100033312199 is a prime.
It is a super-3 number, since 3×1000333122013 (a number of 34 digits) contains 333 as substring.
Together with 100033312199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (100033312241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50016656100 + 50016656101.
It is an arithmetic number, because the mean of its divisors is an integer number (50016656101).
Almost surely, 2100033312201 is an apocalyptic number.
It is an amenable number.
100033312201 is a deficient number, since it is larger than the sum of its proper divisors (1).
100033312201 is an equidigital number, since it uses as much as digits as its factorization.
100033312201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 100033312201 its reverse (102213330001), we get a palindrome (202246642202).
The spelling of 100033312201 in words is "one hundred billion, thirty-three million, three hundred twelve thousand, two hundred one".
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