1000351314311 has 2 divisors, whose sum is σ = 1000351314312. Its totient is φ = 1000351314310.

The previous prime is 1000351314251. The next prime is 1000351314323. The reversal of 1000351314311 is 1134131530001.

It is a strong prime.

It is an emirp because it is prime and its reverse (1134131530001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1000351314311 - 2¹⁰ = 1000351313287 is a prime.

It is a super-2 number, since 2×1000351314311² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000351314341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500175657155 + 500175657156.

It is an arithmetic number, because the mean of its divisors is an integer number (500175657156).

Almost surely, 2^{1000351314311} is an apocalyptic number.

1000351314311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000351314311 is an equidigital number, since it uses as much as digits as its factorization.

1000351314311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 1000351314311 its reverse (1134131530001), we get a palindrome (2134482844312).

The spelling of 1000351314311 in words is "one trillion, three hundred fifty-one million, three hundred fourteen thousand, three hundred eleven".