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10004115130027 is a prime number
BaseRepresentation
bin1001000110010100001110…
…1110101000011010101011
31022102101100222120111222121
42101211003232220122223
52302401411433130102
633135454350332111
72051526204360034
oct221450356503253
938371328514877
1010004115130027
1132077a3203127
121156a45aba037
135774cb88a2c5
142682b7891a8b
1512536b35ab37
hex91943ba86ab

10004115130027 has 2 divisors, whose sum is σ = 10004115130028. Its totient is φ = 10004115130026.

The previous prime is 10004115130007. The next prime is 10004115130057. The reversal of 10004115130027 is 72003151140001.

It is a weak prime.

It is an emirp because it is prime and its reverse (72003151140001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10004115130027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10004115129983 and 10004115130010.

It is not a weakly prime, because it can be changed into another prime (10004115130007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002057565013 + 5002057565014.

It is an arithmetic number, because the mean of its divisors is an integer number (5002057565014).

Almost surely, 210004115130027 is an apocalyptic number.

10004115130027 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004115130027 is an equidigital number, since it uses as much as digits as its factorization.

10004115130027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 10004115130027 its reverse (72003151140001), we get a palindrome (82007266270028).

The spelling of 10004115130027 in words is "ten trillion, four billion, one hundred fifteen million, one hundred thirty thousand, twenty-seven".