Base | Representation |
---|---|
bin | 1001000110010100001110… |
… | …1110101001011001110111 |
3 | 1022102101100222120201112101 |
4 | 2101211003232221121313 |
5 | 2302401411433242241 |
6 | 33135454350402531 |
7 | 2051526204404602 |
oct | 221450356513167 |
9 | 38371328521471 |
10 | 10004115134071 |
11 | 32077a3206173 |
12 | 1156a45b00447 |
13 | 5774cb88c0b6 |
14 | 2682b7893339 |
15 | 12536b35be31 |
hex | 91943ba9677 |
10004115134071 has 2 divisors, whose sum is σ = 10004115134072. Its totient is φ = 10004115134070.
The previous prime is 10004115134029. The next prime is 10004115134141. The reversal of 10004115134071 is 17043151140001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10004115134071 - 29 = 10004115133559 is a prime.
It is a super-3 number, since 3×100041151340713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10004115134011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002057567035 + 5002057567036.
It is an arithmetic number, because the mean of its divisors is an integer number (5002057567036).
Almost surely, 210004115134071 is an apocalyptic number.
10004115134071 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004115134071 is an equidigital number, since it uses as much as digits as its factorization.
10004115134071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 10004115134071 its reverse (17043151140001), we get a palindrome (27047266274072).
The spelling of 10004115134071 in words is "ten trillion, four billion, one hundred fifteen million, one hundred thirty-four thousand, seventy-one".
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