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100042143431 is a prime number
BaseRepresentation
bin101110100101011111…
…0011111011011000111
3100120020002221110011112
41131022332133123013
53114341242042211
6113543030155235
710141065121436
oct1351276373307
9316202843145
10100042143431
113947820008a
121747bab2b1b
139584476a99
144bb08b111d
152907cb188b
hex174af9f6c7

100042143431 has 2 divisors, whose sum is σ = 100042143432. Its totient is φ = 100042143430.

The previous prime is 100042143419. The next prime is 100042143463. The reversal of 100042143431 is 134341240001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100042143431 - 26 = 100042143367 is a prime.

It is a super-2 number, since 2×1000421434312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 100042143397 and 100042143406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100042143491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50021071715 + 50021071716.

It is an arithmetic number, because the mean of its divisors is an integer number (50021071716).

Almost surely, 2100042143431 is an apocalyptic number.

100042143431 is a deficient number, since it is larger than the sum of its proper divisors (1).

100042143431 is an equidigital number, since it uses as much as digits as its factorization.

100042143431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 100042143431 its reverse (134341240001), we get a palindrome (234383383432).

The spelling of 100042143431 in words is "one hundred billion, forty-two million, one hundred forty-three thousand, four hundred thirty-one".